Displays the result Essay

To improve legibility the comments are displayed to the right of every TOM line of code, and not in the standard style. get wind keyin Reads information inputted by keyboard and lineages in the memory board localisation principle keyin load keyin lashings info from the hold on localization of function keyin in to the collector sub deduction Subtracts the inclose localisation minus from the aggregator computer memory display Stores judge in collector register in the cut in localisation of function display print display Displays limit of the store localization principle display on the cover out stop lolly computer political platformme execution minus entropy.1 Initialises a store arrangement minus with the protect 1 in it keyin data 0 Initialises a store position keyin with the harbor 0 in it display data 0 Initialises a store location display with the value 0 in it 2. Write a TOM broadcast that exhibits a exit from the keyboard, multiplies it by 2, reads other do b from the keyboard, multiplies it by 3, and then displays the result. In other words, evaluate 2*a+3*b. read keyin1 Reads data inputted by keyboard and stores in the store location keyin1 load keyin1 Loads data from the store location keyin1 in to the aggregator mult val1 Multiplies the accumulator by the store location val1 store display Stores value in accumulator in the store location display read keyin2.Reads data inputted by keyboard and stores in the store location keyin2 load keyin2 Loads data from the store location keyin2 in to the accumulator mult val2 Multiplies the accumulator by the store location val2 add display Adds the store location display to the accumulator store fundamental Stores value in accumulator in the store location pith print amount Displays contents of the store location centre on the screen stop lucre program execution val1 data 2 Initialises a store location val1 with the value 2 in it val2 data.3 Initialises a store location val2 w ith the value 3 in it keyin1 data 0 Initialises a store location keyin1 with the value 0 in it keyin2 data 0 Initialises a store location keyin2 with the value 0 in it display data 0 Initialises a store location display with the value 0 in it match data 0 Initialises a store location total with the value 0 in it 3. Write a TOM program that displays 2 numbers, entered from the keyboard, in desc demolitioning numerical entrap. read keyin1 Reads data inputted by keyboard and stores in the store location keyin1 read keyin2.Reads data inputted by keyboard and stores in the store location keyin2 load keyin1 Loads data from the store location keyin1 in to the accumulator sub keyin2 Subtracts the store location keyin2 from the accumulator jifz note Transfers ascendancy to the teaching lower if the zero flag is set print keyin1 Displays contents of the store location keyin1 on the screen print keyin2 Displays contents of the store location keyin2 on the screen stop Stops program execut ion lower print keyin2 Displays contents of the store location keyin2 on the screen print keyin1.Displays contents of the store location keyin1 on the screen stop Stops program execution keyin1 data 0 Initialises a store location keyin1 with the value 0 in it keyin2 data 0 Initialises a store location keyin2 with the value 0 in it 4. Write a TOM program that reads a number N from the keyboard and displays the summation of all integers from 1 to N i. e. 1+2+3+ +N. read keyin.Reads data inputted by keyboard and stores in the store location keyin loop load sofar Loads data from the store location sofar in to the accumulator add one Adds the store location one to the accumulator store sofar Stores value in accumulator in the store location sofar add total Adds the store location total to the accumulator store total Stores value in accumulator in the store location total load sofar Loads data from the store location sofar in to the accumulator sub keyin Subtracts the store location keyi n from the accumulator jifn loop.Transfers control to the centering loop if the sign flag is set print total Displays contents of the store location total on the screen stop Stops program execution keyin data 0 Initialises a store location keyin with the value 0 in it one data 1 Initialises a store location one with the value 1 in it sofar data 0 Initialises a store location sofar with the value 0 in it total data 0 Initialises a store location total with the value 0 in it Alternatively, a to a greater extent mathematical approach would be to use the below program.Observing the numbers inputted and outputted from the above program, I was able to find a relationship between the two numbers, this can be summarised by the below statute (N x 0. 5) + 0. 5 x N = TOTAL The program using the above formula is simpler to write, uses far less processor cycles, and therefore far much efficient. read keyin Reads data inputted by keyboard and stores in the store location keyin load keyin Load s data from the store location keyin in to the accumulator mult val Multiplies.the accumulator by the store location val add val Adds the store location val to the accumulator mult keyin Multiplies the accumulator by the store location keyin store total Stores value in accumulator in the store location total print total Displays contents of the store location total on the screen stop Stops program execution keyin data 0 Initialises a store location keyin with the value 0 in it val data .5 Initialises a store location val with the value 0. 5 in it total data 0 Initialises a store location total with the value 0 in it TOM2 1. A mobile peal company, Odear, makes a monthly standing management of i 12.50 and charges 5 pence per local call. Write a TOM program that reads the amount of calls made and displays the total monthly bill. read calls Reads data inputted by keyboard and stores in the store location calls load calls Loads data from the store location calls in to the accumulator m ult wander Multiplies the accumulator by the store location ordinate add standing Adds the store location standing to the accumulator store total Stores value in accumulator in the store location total print total Displays contents of the store location total on the screen stop Stops program execution total data.0 Initialises a store location total with the value 0 in it calls data 0 Initialises a store location calls with the value 0 in it standing data 12. 50 Initialises a store location standing with the value 12. 50 in it footstep data . 05 Initialises a store location rate with the value . 05 in it 2. Expand your program of (1) so that the program rises back to the beginning, ready to calculate another bill instead of ending. start read calls Reads data inputted by keyboard and stores in the store location calls load calls Loads data from the store location calls in to the accumulator mult rate.Multiplies the accumulator by the store location rate add standing Adds the stor e location standing to the accumulator store total Stores value in accumulator in the store location total print total Displays contents of the store location total on the screen jump start Transfers control to the instruction start stop Stops program execution total data 0 Initialises a store location total with the value 0 in it calls data 0 Initialises a store location calls with the value 0 in it standing data 12. 50 Initialises a store location standing with the value 12. 50 in it rate data .05 Initialises a store location rate with the value . 05 in it 3. Whats wrong with the program in (2)? The program has no way of ending (normally), and will therefore loop continuously. 4. Modify (2) so that if the user enters 0 for the number of units the program terminates. start read calls Reads data inputted by keyboard and stores in the store location calls load calls Loads data from the store location calls in to the accumulator sub check Subtracts the store location check from the ac cumulator jifz end Transfers control to the instruction end if the zero flag is set mult rate.Multiplies the accumulator by the store location rate add standing Adds the store location standing to the accumulator store total Stores value in accumulator in the store location total print total Displays contents of the store location total on the screen jump start Transfers control to the instruction start end stop Stops program execution total data 0 Initialises a store location total with the value 0 in it calls data 0 Initialises a store location calls with the value 0 in it standing data 12. 50 Initialises a store location standing with the value 12. 50 in it rate data .05 Initialises a store location rate with the value . 05 in it check data 0 Initialises a store location check with the value 0 in it 5. Now modify (4) so that the user can tell the system how umteen bills to calculate and the program terminates after running that many times. read billnum Reads data inputted by key board and stores in the store location billnum start read calls Reads data inputted by keyboard and stores in the store location calls load calls Loads data from the store location calls in to the accumulator mult rate Multiplies the accumulator by the store location rate add standing.Adds the store location standing to the accumulator store total Stores value in accumulator in the store location total print total Displays contents of the store location total on the screen load billnum Loads data from the store location billnum in to the accumulator sub billsub Subtracts the store location billsub from the accumulator store billnum Stores value in accumulator in the store location billnum jifz end Transfers control to the instruction end if the zero flag is set jump start.Transfers control to the instruction start end stop Stops program execution total data 0 Initialises a store location total with the value 0 in it calls data 0 Initialises a store location calls with the value 0 in it standing data 12. 50 Initialises a store location standing with the value 12. 50 in it rate data . 05 Initialises a store location rate with the value . 05 in it billnum data 0 Initialises a store location billnum with the value 0 in it billsub data 1 Initialises a store location billsub with the value 1 in it 6. Finally, modify the program of (5) so that the user can first enter the price per unit, and the standing charge.Read rate Reads data inputted by keyboard and stores in the store location rate read standing Reads data inputted by keyboard and stores in the store location standing read billnum Reads data inputted by keyboard and stores in the store location billnum start read calls Reads data inputted by keyboard and stores in the store location calls load calls Loads data from the store location calls in to the accumulator mult rate Multiplies the accumulator by the store location rate add standing.Adds the store location standing to the accumulator store total Stores va lue in accumulator in the store location total print total Displays contents of the store location total on the screen load billnum Loads data from the store location billnum in to the accumulator sub billsub Subtracts the store location billsub from the accumulator store billnum Stores value in accumulator in the store location billnum jifz end Transfers control to the instruction end if the zero flag is set jump start.Transfers control to the instruction start end stop Stops program execution total data 0 Initialises a store location total with the value 0 in it calls data 0 Initialises a store location calls with the value 0 in it standing data 0 Initialises a store location standing with the value 0 in it rate data 0 Initialises a store location rate with the value 0 in it billnum data 0 Initialises a store location billnum with the value 0 in it billsub data 1 Initialises a store location billsub with the value 1 in it Modifications in TOM2 In question 1, the program initialise s four store locations rate to store the standard call rate of 0. 5, standing to store the standing charge of 12. 50, calls to store the number of calls made and total to store the total bill.The programs reads a value inputted by the user (number of calls), multiplies this value by the call rate, adds the standing order and displays it. psyche 2 introduces a loop after the total has been displayed to the start of the program so that user may calculate another bill, this however is not ideal as there is no correct way to terminate the program normally. Question 4 combats this problem by allowing the user to enter 0 to terminate the program. This is done by introducing an additional store location called check with the value 0 assigned to it.The program subtracts check from the number of calls entered, if the result is 0 (0 0 = 0) then the zero flag is set, the jifz statement then transfers control to the end of the program, where it terminates normally. Question 5, in addition to the store location used in question 1 introduces two more billnum to store the number of bills required and billsub, a store location containing the value 1. The user initially enters the number of bills required, this is stored in billnum, the program then calculates the bill in same way as question 1.After the bill has been displayed, the program subtracts billsub (1) from the number of bills, if the result is zero (ie no more bill to calculate) the zero flag is set, and using the jifz statement jumps to the end of the program. If the zero flag is not set (more bills to calculate) the program is looped back to enter more bill details. Question 6, allows the user to enter the standing charge, rate of calls and number of bills before the bills are calculated, these are stored in their respective locations (standing, rate and billnum) before the program continues to execute in the same way as question 5.CSO Tutorial 4 Exercise 2. 1 We wish to compare the performance of two assorted machines M1 and M2. The following measurements have been made on these machines Program Time on M1 Time on M2 1 10 seconds 5 seconds 2 3 seconds 4 seconds Which machine is quicker for each program and by how much? For program 1, M2 is 5 seconds(or 100%) faster than M1. For program 2, M1 is 1 second (or 25%) faster than M2. Exercise 2. 2 Consider the two machines and programs in Exercise 2. 1. The following additional measurements were made Program.Instructions kill on M1 Instructions executed on M2 1 200 x 106 160 x 106 Find the instruction execution rate (instructions per second) for each machine running program 1. Instructions executed = Instructions per second (instruction execution rate) time(seconds) M1 200000000 = 20000000 10 = 20 x 106 Instructions per second or 20 Million Instructions per second M2 160000000 = 32000000 5 = 32 x 106 Instructions per second or 32 Million Instructions per second Exercise 2. 3 If the clock rates of machines M1 and M2 in Ex 2.1 are 200 MHz and 3 00 MHz respectively, find the clock cycles per instruction (CPI) for program 1 on both machines using the data in Ex 2. 1 & 2. 2. Clock rate = clock cycles per instruction (CPI) Instruction execution rate M1 200000000 = 10 clock cycles per instruction (CPI) 20000000 M2 300000000 = 9. 375 clock cycles per instruction (CPI) 32000000 Question 4 Draw a full flowchart of the final TOM program produced at the end of exercise TOM2. This should include all the instructions, loops and all the program labels in the appropriate places.